Differences between revisions 5 and 13 (spanning 8 versions)

For loops

a)

{{{# 0 1 2 3 }}}

Insert an expression in ... to get the results.

Solution:

b)

   1 for i in 4*range(4):
   2      print i
   3   
   4 0 0
   5 0 1
   6 0 2
   7 0 3
   8 1 0
   9 1 1
  10 1 2
  11 1 3
  12 2 0
  13 2 1
  14 2 2
  15 2 3
  16 3 0
  17 3 1
  18 3 2
  19 3 3

What are the corresponding loops?

Solution:

Data types

A=dict([('a',1),('b',2)])

Please specify the data types:

A is a ...
'a' is a ...
1 is a ...
('a',1) is a ...
[('a',1),('b',2)] is a ...

Provide an alternative way to assign A

Scipy numeric types

from scipy import *

One byte consists of eight bit and covers the value range of 0..255 (uint8, unsigned integer) or -128..127.

   1 b=int8(128)
   2 -128 # Invalid range
   3 
   4 b.nbytes
   5 1

a)

What is the value range of the following types and how many bytes are allocated in the memory?

bool8
uint8, int8
uint16, int16
uint32, int32
uint64, uint64

Solution:

b)

How many bytes are allocated in the memory by these floating point types?

float32, float64, float96
complex64, complex128, complex192

Solution:

Data structures

a)

   1 D={'A':array(range(10)),'B':array(range(10))+1}

Which keys contains the dictionary D
Get the keys with the method D.keys()
Display all values of D using the method .values()
Display array A
Display the elements 3:6 of arrays B
Set this elements to 0
Insert a new key-values pair C:array(range(0,10,-1)) into D

Solution:

Reading and practicing

Install python and ipython on your computer and read through the tutorial which comes with the documentation. There are translations in other languages:

-  ⇤ ← Revision 5 as of 2008-10-30 10:42:22 → 
  Size: 2396
  Editor: anonymous
  Comment:
+   ← Revision 13 as of 2008-11-10 15:22:41 → ⇥
  Size: 2365
  Editor: JohannesRoehrs
  Comment:
-Deletions are marked like this.
+Additions are marked like this.
 Line 11:
-{{{#!python
for ...:
     print i
+{{{#
-Line 23:
+Line 20:
-[[/Solution1A|Solution]]
+Solution:
-Line 26:
+Line 23:
-Line 28:
+Line 24:
-for ... in zip(range(0,4,1),range(4,0,-1)):
     print i,j
+for i in 4*range(4):
     print i
-Line 31:
+Line 27:
-4
1 3
2 2
3 1
}}}

 * Insert an expression in {{{...}}} to get the results.

[[/Solution1B|Solution]]


== c) ==
{{{
-Line 64:
+Line 47:
-[[/Solution1C|Solution]]
+Solution:
-Line 66:
+Line 49:
+= Data types =

{{{
A=dict([('a',1),('b',2)])
}}}

Please specify the data types:

 
 * A is a ...
 * 'a' is a ...
 * 1 is a ...
 * ('a',1) is a ...
 * [('a',1),('b',2)] is a ...

Provide an alternative way to assign A
 Line 92:
-[[/Solution2A|Solution]]
+Solution:
-Line 103:
+Line 102:
-[[/Solution2B|Solution]]
+Solution:
-Line 113:
+Line 112:
+ * Display all values of {{{D}}} using the method {{{.values()}}}
 Line 117:
- * Display all values of {{{D}}} using the method {{{.values()}}}
-Line 119:
+Line 118:
-[[/Solution3A|Solution]]
+Solution: